In this episode of Engineer In Training Exam TV, Justin walks you through a Fundamentals of Engineering Exam Review of Distance Formula.
He will start with defining the Pythagorean Theorem and how the Distance formula relates, then finish off with a quick example of how to find the distance between any two given points.
This Fundamentals of Engineering Exam Review of Distance Formula is part of the global subject Mathematics.
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Hey what’s going on everyone, it’s Justin Dickmeyer from EngineerInTrainingExam.com.
In today’s video we are going to present a Fundamentals of Engineering Exam Review of Distance Formula.
We’ll start off this tutorial discussing the theory and then get in to working a problem.
So let’s start off our Fundamentals of Engineering Exam Review of Distance Formula by defining exactly what the Distance Formula is.
So what is the distance formula?
the distance formula is a restatement of
the Pythagorean theorem packaged up into
a simple equation that will allow us to
find the distance between two given
points so let’s consider the two points
negative 2 1 and 1 5 now it’s the
standard process to find the distance to
the of these two points we can simply
graph them and then draw a straight line
between them and then develop a triangle
as such would this be inside a this side
be inside being the hypotenuse which is
the distance between the two points be
inside C so graphically once again it’s
easy to find what C is just using the
Pythagorean theorem which is a squared
plus B squared is equal to C squared so
using this process we can simply find
out that if this is a point 1 5 and this
is point negative 2 1 that we can see
that a is going to be 3 and B is going
to be 4 so if we just plug that into the
Pythagorean theorem here we find that 3
squared plus 4 squared is equal to C
squared and just calculating that out we
find that it is equal to 9 plus 16 which
is equal to 25 which is equal to C
squared and we find that the hypotenuse
or the distance between these two points
is the square root of 25 which is equal
five so this this method obviously holds
true in any case however the the
like I said repackages this formula into
a simple a simple equation that we can
just quickly plug in any two given
points in a coordinate system to figure
out what the distance is between those
so the distance formula states that D is
equal to the square root of x2 minus x1
squared plus y squared and all that is
under the square root now this is of
course if we’re given x1 y1 and x2 y2 so
all we need to do is plug this given
information into the distance formula
and we will be able to determine the
distance between those two points so
let’s look at a quick example here let’s
say that we’re given the points negative
3 negative 2 and we’re given the point 5
2 now we can go ahead and graph this
make a triangle determine the sides a
and B and solve for the hypotenuse C or
we can go ahead and just take our
distance formula and plug in the
information that we are given which we
will do in this case so D is equal to
the square root of x2 which in this case
is 5 minus x1 which is negative 3 all
that squared plus y2 which is 2 minus y1
which is negative 2 all squared so
working that out we get we get the
square root of 8 squared plus 4 squared
which comes down to the square root of
80 and just thrown that into our
calculator real quick
the distance between these two given
points is eight point nine four so
that’s essentially it guys not much to
it it just once again is a reach the
distance formula is once again a
restatement of the Pythagorean theorem
it just allows us a quick concise way to
plug in two given points and define real
quickly what the distance is between
those two points so if you guys have any
questions go ahead and visit my site at
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the other videos I got posted there as
well as here on YouTube leave comments
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check it out and look forward to talking
to you guys soon all right take care
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