In this episode of Engineer In Training Exam TV, Justin walks you through a Fundamentals of Engineering Exam Review of Distance Formula.

He will start with defining the Pythagorean Theorem and how the Distance formula relates, then finish off with a quick example of how to find the distance between any two given points.

This Fundamentals of Engineering Exam Review of Distance Formula is part of the global subject Mathematics.

Having served over 1.5 million lessons in 150 different countries, it’s safe to say we have been in the trenches.

In the trenches working with those who are taking the exam for the first time, either fresh out of college or having taken a few years off from the books.

In the trenches working with those who have already attempted the exam, maybe multiple times, and can’t seem to crack the code.

In the trenches working with those who have been away from the books for ages, from standardized testing for the same amount of time, and can’t fathom taking on this beast of an exam.

And every iteration in between.

Every student’s situation is unique, but the building blocks of what success looks like are always the same.

Click below to register for the FREE myFE Exam Academy Course.

Once you are registered, you’ll get instant access to a proven roadmap, strategies and tactics…

Straight to your email box.

REGISTER NOW!

Hey what’s going on everyone, it’s Justin Dickmeyer from EngineerInTrainingExam.com.

In today’s video we are going to present a Fundamentals of Engineering Exam Review of Distance Formula.

We’ll start off this tutorial discussing the theory and then get in to working a problem.

So let’s start off our Fundamentals of Engineering Exam Review of Distance Formula by defining exactly what the Distance Formula is.

So what is the distance formula?

Well essentially

the distance formula is a restatement of

the Pythagorean theorem packaged up into

a simple equation that will allow us to

find the distance between two given

points so let’s consider the two points

negative 2 1 and 1 5 now it’s the

standard process to find the distance to

the of these two points we can simply

graph them and then draw a straight line

between them and then develop a triangle

as such would this be inside a this side

be inside being the hypotenuse which is

the distance between the two points be

inside C so graphically once again it’s

easy to find what C is just using the

Pythagorean theorem which is a squared

plus B squared is equal to C squared so

using this process we can simply find

out that if this is a point 1 5 and this

is point negative 2 1 that we can see

that a is going to be 3 and B is going

to be 4 so if we just plug that into the

Pythagorean theorem here we find that 3

squared plus 4 squared is equal to C

squared and just calculating that out we

find that it is equal to 9 plus 16 which

is equal to 25 which is equal to C

squared and we find that the hypotenuse

or the distance between these two points

is the square root of 25 which is equal

to

five so this this method obviously holds

true in any case however the the

distance formula

like I said repackages this formula into

a simple a simple equation that we can

just quickly plug in any two given

points in a coordinate system to figure

out what the distance is between those

two points

so the distance formula states that D is

equal to the square root of x2 minus x1

squared plus y squared and all that is

under the square root now this is of

course if we’re given x1 y1 and x2 y2 so

all we need to do is plug this given

information into the distance formula

and we will be able to determine the

distance between those two points so

let’s look at a quick example here let’s

say that we’re given the points negative

3 negative 2 and we’re given the point 5

2 now we can go ahead and graph this

make a triangle determine the sides a

and B and solve for the hypotenuse C or

we can go ahead and just take our

distance formula and plug in the

information that we are given which we

will do in this case so D is equal to

the square root of x2 which in this case

is 5 minus x1 which is negative 3 all

that squared plus y2 which is 2 minus y1

which is negative 2 all squared so

working that out we get we get the

square root of 8 squared plus 4 squared

which comes down to the square root of

80 and just thrown that into our

calculator real quick

the distance between these two given

points is eight point nine four so

that’s essentially it guys not much to

it it just once again is a reach the

distance formula is once again a

restatement of the Pythagorean theorem

it just allows us a quick concise way to

plug in two given points and define real

quickly what the distance is between

those two points so if you guys have any

questions go ahead and visit my site at

engineer in training exam comm check out

the other videos I got posted there as

well as here on YouTube leave comments

suggestions you know email contact me

I’m always open to help you guys out in

any way that I’m able once again

everything’s free for you guys to use so

check it out and look forward to talking

to you guys soon all right take care

—

Follow Prepineer Online Here:

Instagram: https://instagram.com/prepineer

Prepineer Facebook: https://facebook.com/prepineer

EngineerInTrainingExam Facebook: https://www.facebook.com/EngineerInTrainingExam

Snapchat: https://www.snapchat.com/add/prepineer

Website: https://www.Prepineer.com

Website: https://www.EngineerInTrainingExam.com

Twitter: https://twitter.com/prepineer

Passing the FE Exam – Engineering Advice (private Facebook group): https://www.facebook.com/groups/372061059925853/

## Leave a Reply